Given a roman numeral, convert it to an integer.
Input is guaranteed to be within the range from 1 to 3999.
public class Solution {
Map<Character,Integer>map=new HashMap<Character,Integer>();
String roman="MDCLXVI";
{
map.put('I', 1);
map.put('V', 5);
map.put('X', 10);
map.put('L', 50);
map.put('C', 100);
map.put('D', 500);
map.put('M', 1000);
}
public int romanToInt(String s) {
int result=0;
if(s==null||s.length()==0)
{
return 0;
}
if(s.length()==1){
return map.get(s.charAt(0));
}
int startIndex=0;
int endIndex=0;
for(int i=0;i<roman.length();i++)
{
startIndex=s.indexOf(roman.charAt(i));
if(startIndex>=0){
for(endIndex=startIndex;endIndex<s.length();endIndex++){
if(s.charAt(endIndex)!=s.charAt(startIndex))
{
break;
}
}
break;
}
}
result=(endIndex-startIndex)*map.get(s.charAt(startIndex));
if(startIndex>0){
result-=romanToInt(s.substring(0,startIndex));
}
if(endIndex<s.length()){
result+=romanToInt(s.substring(endIndex));
}
return result;
}
}原文地址:http://blog.csdn.net/jiewuyou/article/details/39226743