标签:blog io os for 2014 div sp log c
//给你n个数,两个数之间可以+。-两个运算 得出的所有结果只要有能被k正除,输出Divisible,否则Not divisible
# include <iostream>
# include <stdio.h>
# include <algorithm>
# include <string.h>
using namespace std;
int dp[10010][110];//第一维代表几个数相加,第二位为几个数相加%k后的余数
int b[10010];
int main()
{
int n,k,i,j,t;
while(~scanf("%d %d",&n,&k))
{
for(i=1; i<=n; i++)
scanf("%d",&b[i]);
for(i=0; i<=n; i++)
for(j=0; j<=k-1; j++)
dp[i][j]=0;
dp[0][0]=1;
for(i=1; i<=n; i++)
{
for(j=0; j<=k-1; j++)
{
if(dp[i-1][j]==1)
{
t=((j+b[i])%k+k)%k;//可能有负数,注意取余
dp[i][t]=1;
t=((j-b[i])%k+k)%k;
dp[i][t]=1;
}
}
}
if(dp[n][0]==1)
printf("Divisible\n");
else
printf("Not divisible\n");
}
return 0;
}
标签:blog io os for 2014 div sp log c
原文地址:http://blog.csdn.net/lp_opai/article/details/39229399