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Single Number II

时间:2014-09-13 20:06:45      阅读:155      评论:0      收藏:0      [点我收藏+]

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Given an array of integers, every element appears three times except for one. Find that single one.

Note:

Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

 1 class Solution {
 2 public:
 3     int singleNumber(int A[], int n) {
 4         
 5         unordered_map<int, int> singleMap;
 6         for(int i = 0; i < n; i++)
 7         {
 8             if(singleMap.find(A[i]) != singleMap.end())
 9                 singleMap[ A[i] ]++;
10             else
11                 singleMap[ A[i] ] = 1;
12         }
13         
14         for(unordered_map<int, int>::iterator it = singleMap.begin(); it != singleMap.end(); it++)
15         {
16             if(it->second != 3)
17                 return it->first;
18         }
19     }
20 };

 

Single Number II

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原文地址:http://www.cnblogs.com/YQCblog/p/3970202.html

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