标签:des style blog http color io os java ar
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4093 Accepted Submission(s): 2933
Mean:
略
analyse:
经典的母函数运用题。
Time complexity:O(n^3)
Source code:
// Memory Time
// 1347K 0MS
// by : Snarl_jsb
// 2014-09-18-13.40
#include<algorithm>
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<iostream>
#include<vector>
#include<queue>
#include<stack>
#include<map>
#include<string>
#include<climits>
#include<cmath>
#define N 1000010
#define LL long long
using namespace std;
int cnt[100],c1[100],c2[100];
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(0);
// freopen("C:\\Users\\ASUS\\Desktop\\cin.cpp","r",stdin);
// freopen("C:\\Users\\ASUS\\Desktop\\cout.cpp","w",stdout);
int Cas;
cin>>Cas;
while(Cas--)
{
for(int i=1;i<=26;++i)
cin>>cnt[i];
memset(c1,0,sizeof(c1)); //以防后面越界,最好全部赋值为0
memset(c2,0,sizeof(c2));
for(int i=0;i<=cnt[1]&&i<=50;++i)
c1[i]=1;
for(int i=2;i<=26;++i)
{
for(int j=0;j<=50;++j)
{
for(int k=0;k+j<=50&&k<=cnt[i]*i;k+=i)
{
c2[k+j]+=c1[j];
}
}
for(int j=0;j<=50;++j)
{
c1[j]=c2[j];
c2[j]=0;
}
}
long long ans=0;
for(int i=1;i<=50 ;++i)
ans+=c1[i];
cout<<ans<<endl;
}
return 0;
}
组合数学 - 母函数的运用 + 模板 --- hdu : 2082
标签:des style blog http color io os java ar
原文地址:http://www.cnblogs.com/acmer-jsb/p/3979112.html