标签:des style blog color io os java ar strong
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 13129 Accepted Submission(s): 9285
Mean:
给你一个n,问你n的拆分有多少种。
analyse:
经典的母函数运用题,不解释。
Time complexity:O(n^3)
Source code:
// Memory Time
// 1347K 0MS
// by : Snarl_jsb
// 2014-09-18-15.21
#include<algorithm>
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<iostream>
#include<vector>
#include<queue>
#include<stack>
#include<map>
#include<string>
#include<climits>
#include<cmath>
#define N 1000010
#define LL long long
using namespace std;
int c1[300],c2[300];
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(0);
// freopen("C:\\Users\\ASUS\\Desktop\\cin.cpp","r",stdin);
// freopen("C:\\Users\\ASUS\\Desktop\\cout.cpp","w",stdout);
int n;
while(cin>>n)
{
memset(c1,0,sizeof(c1));
memset(c2,0,sizeof(c2));
for(int i=0;i<=n;++i)
{
c1[i]=1;
}
for(int i=2;i<=n;i++)
{
for(int j=0;j<=n;++j)
{
for(int k=0;k<=n;k+=i)
{
c2[k+j]+=c1[j];
}
}
for(int j=0;j<=n;++j)
{
c1[j]=c2[j];
c2[j]=0;
}
}
cout<<c1[n]<<endl;
}
return 0;
}
标签:des style blog color io os java ar strong
原文地址:http://www.cnblogs.com/acmer-jsb/p/3979326.html