You‘re given strings J representing the types of stones that are jewels, and S representing the stones you have. Each character in Sis a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so "a" is considered a different type of stone from "A".
Example 1:
Input: J = "aA", S = "aAAbbbb" Output: 3
Example 2:
Input: J = "z", S = "ZZ" Output: 0
Note:
SandJwill consist of letters and have length at most 50.- The characters in
Jare distinct.
思路:
用map统计,扫描一遍S即可。
int numJewelsInStones(string J, string S) { int ret = 0; map<char,int>mp; for(auto ch : S)mp[ch]++; for(int i= 0;i<J.size();j++) { ret += mp[J[i]]; } return ret; }