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在未排序的数组中找到第 k 个最大的元素。请注意,它是数组有序排列后的第 k 个最大元素,而不是第 k 个不同元素。
例如,
给出 [3,2,1,5,6,4] 和 k = 2,返回 5。
注意事项:
你可以假设 k 总是有效的,1 ≤ k ≤ 数组的长度。
详见:https://leetcode.com/problems/kth-largest-element-in-an-array/description/
方法一:
class Solution {
public:
int findKthLargest(vector<int>& nums, int k) {
priority_queue<int,vector<int>,greater<int>> minH;
for(int i=0;i<nums.size();++i)
{
if(minH.size()<k)
{
minH.push(nums[i]);
}
else
{
if(minH.top()<nums[i])
{
minH.pop();
minH.push(nums[i]);
}
}
}
return minH.top();
}
};
方法二:
class Solution {
public:
int partition(vector<int>& nums, int left, int right) {
int pivot = nums[left];
int l = left + 1, r = right;
while (l <= r) {
if (nums[l] < pivot && nums[r] > pivot)
swap(nums[l++], nums[r--]);
if (nums[l] >= pivot) l++;
if (nums[r] <= pivot) r--;
}
swap(nums[left], nums[r]);
return r;
}
int findKthLargest(vector<int>& nums, int k) {
int left = 0, right = nums.size() - 1;
while (true) {
int pos = partition(nums, left, right);
if (pos == k - 1) return nums[pos];
if (pos > k - 1) right = pos - 1;
else left = pos + 1;
}
}
};
参考:https://www.cnblogs.com/grandyang/p/4539757.html
215 Kth Largest Element in an Array 数组中的第K个最大元素
标签:tps wap tor while https public highlight priority --
原文地址:https://www.cnblogs.com/xidian2014/p/8747863.html