HDU - 5053 the Sum of Cube

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2
1 3
2 5

Case #1: 36
Case #2: 224

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
typedef __int64 ll;
using namespace std;

int main() {
    int t, a, b, cas =1 ;
    scanf("%d", &t);
    while (t--) {
        scanf("%d%d", &a, &b);    
        ll sum = 0;
        for (int i = a; i <= b; i++)
            sum += (ll)i * i * i;
        printf("Case #%d: ", cas++);
        printf("%I64d\n", sum);
    }
    return 0;
}

HDU - 5053 the Sum of Cube

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原文地址：http://blog.csdn.net/u011345136/article/details/39620381