标签：nes after 整数 clu follow ant its osi each
Cutting an integer means to cut a K digits long integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 x 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (<= 20). Then N lines follow, each gives an integer Z (10<=Z<=2^31^). It is guaranteed that the number of digits of Z is an even number.
Output Specification:
For each case, print a single line "Yes" if it is such a number, or "No" if not.
Sample Input:
3
167334
2333
12345678
Sample Output:
Yes
No
No
#include<iostream> #include<cmath> #include<vector> using namespace std; int main(){ int a, n, i; cin>>n; for(i=0; i<n; i++){ cin>>a; int cnt=0, copy=a; while(a){ cnt++; a/=10; } int div=pow(10, cnt/2); int x = copy % div, y = copy/div; if(x*y==0) cout<<"No"<<endl; else if(copy%(x*y)==0) cout<<"Yes"<<endl; else cout<<"No"<<endl; } return 0; }
标签：nes after 整数 clu follow ant its osi each
原文地址：https://www.cnblogs.com/mr-stn/p/9161493.html
