标签:leetcode解题报告 算法 面试题 递归 二叉树
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.public class Solution {
ListNode getLeftNodeFromList(ListNode head) {
ListNode next = head;
ListNode current = head;
ListNode pre = head;
while(next!=null) {
next = next.next;
if(next==null) {
break;
}
next = next.next;
if(next==null) {
break;
}
pre = head;
head = head.next;
}
return pre;
}
public TreeNode sortedListToBST(ListNode head) {
if(head==null) {
return null;
}
if(head.next==null) {
return new TreeNode(head.val);
}
ListNode left = getLeftNodeFromList(head);
ListNode mid = left.next;
TreeNode root = new TreeNode(mid.val);
left.next = null;
root.left = sortedListToBST(head);
root.right = sortedListToBST(mid.next);
return root;
}
}LeetCode Convert Sorted List to Binary Search Tree 解题报告
标签:leetcode解题报告 算法 面试题 递归 二叉树
原文地址:http://blog.csdn.net/worldwindjp/article/details/39722643