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LeetCode - Daily Temperatures

时间:2018-09-23 11:29:13      阅读:140      评论:0      收藏:0      [点我收藏+]

标签:pos   length   oss   bre   war   ++   ==   hat   div   

Given a list of daily temperatures, produce a list that, for each day in the input, tells you how many days you would have to wait until a warmer temperature. If there is no future day for which this is possible, put 0 instead.

For example, given the list temperatures = [73, 74, 75, 71, 69, 72, 76, 73], your output should be [1, 1, 4, 2, 1, 1, 0, 0].

Note: The length of temperatures will be in the range [1, 30000]. Each temperature will be an integer in the range [30, 100].

竟然暴力解法也可AC:

class Solution {
    public int[] dailyTemperatures(int[] temperatures) {
        if(temperatures == null || temperatures.length == 0){
            return null;
        }
        int len = temperatures.length;
        int[] res = new int[len];
        for(int i=0; i<len; i++){
            int count = 0;
            int cur = temperatures[i];
            for(int j = i+1; j<len; j++){
                int fu = temperatures[j];
                if(fu > cur){
                    count = j-i;
                    break;
                }
            }
            res[i] = count;
        }
        return res;
    }
}

  

LeetCode - Daily Temperatures

标签:pos   length   oss   bre   war   ++   ==   hat   div   

原文地址:https://www.cnblogs.com/incrediblechangshuo/p/9691945.html

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