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UVA 10330 Power Transmission

时间:2014-10-10 15:52:43      阅读:178      评论:0      收藏:0      [点我收藏+]

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题意:懒得打了。LUCKY CAT 里有 http://163.32.78.26/homework/q10330.htm

第一个网络流题目。每个节点都有一个容量值。需要拆点。拆成i - > i + N  边权为容量值

另外注意B个点 连接方式:s - 集合B

D个点 链接方式 集合D + N -> t汇点

其他看处理就好

#include <map>
#include <set>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <stack>
#include <queue>
#include <cctype>
#include <cstdio>
#include <string>
#include <vector>
#include <climits>
#include <cstdlib>
#include <cstring>
#include <iostream>
#include <algorithm>
#define LL long long
#define PI 3.1415926535897932626
using namespace std;
int gcd(int a, int b) {return a % b == 0 ? b : gcd(b, a % b);}
#define MAXN 250
const int INF = 0x3f3f3f3f ;
int flow[MAXN][MAXN],c[MAXN][MAXN];
int p[MAXN];
int N,M,B,D,src,tag;
void read()
{
    memset(c,0,sizeof(c));
    src = 0; tag = 2 * N + 1;
    for (int i = 1; i <= N; i++)
    {
        int tmp;
        scanf("%d",&tmp);
        c[i][i + N] = tmp;
    }
    scanf("%d",&M);
    for (int i = 1; i <= M; i++)
    {
        int u,v,w;
        scanf("%d%d%d",&u,&v,&w);
        c[u + N][v] = w;
    }
    scanf("%d%d",&B,&D);
    for (int i = 1; i <= B; i++)
    {
        int tmp;
        scanf("%d",&tmp);
        c[0][tmp] = INF;
    }
    for (int i = 1; i <= D; i++)
    {
        int tmp;
        scanf("%d",&tmp);
        c[tmp + N][tag] = INF;
    }
}
int Edmonds_karp(int src,int tag)
{
    memset(flow,0,sizeof(flow));
    int ans = 0;
    queue<int>q;
    while (!q.empty()) q.pop();
    int a[MAXN];
    while (true)
    {
        memset(a,0,sizeof(a));
        a[src] = INF;
        q.push(src);
        while (!q.empty())
        {
            int u = q.front(); q.pop();
            for (int v = 0; v <= tag; v++)
                if (!a[v] && c[u][v] > flow[u][v])
            {
                p[v] = u;
                q.push(v);
                a[v] = min(a[u],c[u][v] - flow[u][v]);
            }
        }
        if (a[tag] == 0) break;
        for (int u = tag; u != src; u = p[u])
        {
            flow[p[u]][u] += a[tag];
            flow[u][p[u]] -= a[tag];
        }
        ans += a[tag];
    }
    return ans;
}
int main()
{
    //freopen("sample.txt","r",stdin);
    while (scanf("%d",&N)!=EOF)
    {
        read();
        printf("%d\n",Edmonds_karp(src,tag));
    }
    return 0;
}

 

UVA 10330 Power Transmission

标签:style   blog   http   color   io   os   ar   for   sp   

原文地址:http://www.cnblogs.com/Commence/p/4015641.html

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