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leetcode-876 Middle of the Linked List

时间:2018-10-27 14:52:07      阅读:101      评论:0      收藏:0      [点我收藏+]

标签:order   想法   指针   NPU   中间   span   object   example   lis   

Given a non-empty, singly linked list with head node head, return a middle node of linked list.

If there are two middle nodes, return the second middle node.

Example 1:

Input: [1,2,3,4,5]
Output: Node 3 from this list (Serialization: [3,4,5])
The returned node has value 3.  (The judge‘s serialization of this node is [3,4,5]).
Note that we returned a ListNode object ans, such that:
ans.val = 3, ans.next.val = 4, ans.next.next.val = 5, and ans.next.next.next = NULL.

Example 2:

Input: [1,2,3,4,5,6]
Output: Node 4 from this list (Serialization: [4,5,6])
Since the list has two middle nodes with values 3 and 4, we return the second one.

Note:

  • The number of nodes in the given list will be between 1 and 100.


想法:通过两个指针,一个称为快指针,一个称为慢指针,慢指针更新时指向它的下一个节点,而快指针更新时指向它的下下个节点,当快指针到达链表尾端时,慢指针刚好指向链表中间的位置。

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     struct ListNode *next;
 * };
 */
struct ListNode* middleNode(struct ListNode* head) {
    struct ListNode* fast = head;
    struct ListNode* slow = head;
    while(fast && fast->next){
        fast = fast->next->next;
        slow = slow ->next;
    }
    return slow;
}

leetcode-876 Middle of the Linked List

标签:order   想法   指针   NPU   中间   span   object   example   lis   

原文地址:https://www.cnblogs.com/tingweichen/p/9860884.html

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