码迷,mamicode.com
首页 > 其他好文 > 详细

LC 593. Valid Square

时间:2019-01-16 17:23:28      阅读:155      评论:0      收藏:0      [点我收藏+]

标签:ted   gre   nbsp   poi   fast   order   LIDS   public   run   

Given the coordinates of four points in 2D space, return whether the four points could construct a square.

The coordinate (x,y) of a point is represented by an integer array with two integers.

Example:

Input: p1 = [0,0], p2 = [1,1], p3 = [1,0], p4 = [0,1]
Output: True

 

Note:

  1. All the input integers are in the range [-10000, 10000].
  2. A valid square has four equal sides with positive length and four equal angles (90-degree angles).
  3. Input points have no order.

 

从边入手,如果四个点不重合,那么形成的四条边加两个对角线只可能有两个情况,且对角线要长。

Runtime: 16 ms, faster than 57.63% of Java online submissions for Valid Square.

 

class Solution {
  public boolean validSquare(int[] p1, int[] p2, int[] p3, int[] p4) {
    int[][] p = {{p1[0],p1[1]},{p2[0],p2[1]},{p3[0],p3[1]},{p4[0],p4[1]}};
    int cnt = 0;
    int[] len = new int[6];
    for(int i=0; i<4; i++){
      for(int j=i+1; j<4 ;j++){
        if(p[i][0] == p[j][0] && p[i][1] == p[j][1]) return false;
        len[cnt++] = (p[i][0]-p[j][0])*(p[i][0]-p[j][0])+(p[i][1]-p[j][1])*(p[i][1]-p[j][1]);
      }
    }
    Arrays.sort(len);
    if(len[0] == len[2] && len[4] == len[5] && len[4] > len[1]){
      return true;
    }
    return false;
  }
}

 

LC 593. Valid Square

标签:ted   gre   nbsp   poi   fast   order   LIDS   public   run   

原文地址:https://www.cnblogs.com/ethanhong/p/10278001.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!