django创建路径导航

request.current_menu_id = None
 
request.breadcrumb_list = [{‘title‘: ‘首页‘, ‘url‘: ‘/index/‘}]
# 登陆后不需要权限
for i in settings.NO_PERMISSION_LIST:
    if re.match(i, url):
        return

for permission in permission_dict.values():
    
    if re.match(r‘^{}$‘.format(permission[‘url‘]), url):
        pid = permission.get(‘pid‘)
        id = permission.get(‘id‘)
        
        if pid:    #存在pid,是普通权限
            request.current_menu_id = pid
            request.breadcrumb_list.append(           #添加二级菜单路径
                {‘title‘: permission_dict[str(pid)][‘title‘], ‘url‘: permission_dict[str(pid)][‘url‘]})
            request.breadcrumb_list.append({‘title‘: permission[‘title‘], ‘url‘: permission[‘url‘]})   #添加普通权限路径
         
        else:      #pid不存在,表示访问的是二级菜单
            request.current_menu_id = id
            request.breadcrumb_list.append({‘title‘: permission[‘title‘], ‘url‘: permission[‘url‘]})   #添加二级菜单路径
        
        return

@register.inclusion_tag(‘breadcrumb.html‘)     #inclusion中的内容 : 将字典传入breadcrumb.html,注意传入参数
def breadcrumb(request):
    return {‘breadcrumb_list‘: request.breadcrumb_list}

<div>
    <ol class="breadcrumb no-radius no-margin" style="border-bottom: 1px solid #ddd;">
 
        {% for breadcrumb in breadcrumb_list %}
            {% if forloop.last %}
                <li class="active">{{ breadcrumb.title }}</li>
            {% else %}
                <li><a href="{{ breadcrumb.url }}">{{ breadcrumb.title }}</a></li>
            {% endif %}
        {% endfor %}
    </ol>
</div>