标签:des style blog io ar for strong sp div
| Time Limit: 3000MS | Memory Limit: 65536K | |
| Total Submissions: 33178 | Accepted: 13792 |
Description
Input
Output
Sample Input
abcd aaaa ababab .
Sample Output
1 4 3
Hint
Source
用next数组求出整个数组的最大前缀,如果整个串是用循环节组成的,那么 n - next[n] 也就是最小循环节,验证最小循环节会被n整出。
#include <cstdio>
#include <cstring>
#include <algorithm>
int next[1100000] ;
char str[1100000] ;
void getnext(int l)
{
int j = 0 , k = -1 ;
next[0] = -1 ;
while(j < l)
{
if( k == -1 || str[j] == str[k] )
{
j++ ;
k++ ;
next[j] = k ;
}
else
k = next[k] ;
}
}
int main()
{
int l , m ;
while(scanf("%s", str)!=EOF)
{
if( str[0] == '.' ) break;
l = strlen(str);
getnext(l) ;
m = next[l];
if( l % (l-m) != 0 )
printf("1\n");
else
{
m = l / ( l-m );
printf("%d\n", m);
}
memset(str,0,sizeof(str));
}
return 0;
}
poj2406--Power Strings(KMP求最小循环节)
标签:des style blog io ar for strong sp div
原文地址:http://blog.csdn.net/winddreams/article/details/40268107