*赤裸裸的数学题： 
证明过程：
依据三角函数： 
1.tan(a+b) = ( tan(a) + tan(b) ) / (1 – tan(a) * tan(b) )
2.tan( arctan(x) ) = x

arctan(1/s) = arctan(1/u)+arctan(1/v)
所以得1/s = tan( arctan(1/u)+arctan(1/v) ) 
          = (tan(arctan(1/u)) + tan(arctan(1/v)))/(1-tan(arctan(1/u))*tan(arctan(1/v)))
          = (1/u + 1/v) / (1 - 1/(uv))
所以解得 uv = 1 + us + vs
v=(1+us)/(u-s)
所以v*u-s*u-s*v
   =u(1+us)/(u-s)-s(1+us)/(u-s)-su
   =1
*/ 

#include<cstdio>
#include<cstring>
#include<cmath>
#include<iostream> 
#include<algorithm> 
using namespace std;
int main()
{
	int T,a,b;
	cin>>T;
	while(T--)
	{
		cin>>a>>b;
		cout<<1<<endl;   //会不会有点不可思议，但是它就是这么水。。。
		
	}
	
	return 0;
}