标签：include 输入格式 输入输出 字典序 方案 cin ace cout color
猪猪hanke得到了一只鸡
猪猪Hanke特别喜欢吃烤鸡（本是同畜牲，相煎何太急！）Hanke吃鸡很特别，为什么特别呢？因为他有10种配料（芥末、孜然等），每种配料可以放1—3克，任意烤鸡的美味程度为所有配料质量之和
现在，Hanke想要知道，如果给你一个美味程度，请输出这10种配料的所有搭配方案
输入格式：
一行,n<=5000
输出格式：
第一行，方案总数
第二行至结束，10个数，表示每种配料所放的质量
按字典序排列。
如果没有符合要求的方法，就只要在第一行输出一个“0”
#include<iostream> using namespace std; int main() { int a, b, c, d, e, f, g, h, i, j, in, x = 0; cin >> in; for (a = 1; a <= 3; a++) { for (b = 1; b <= 3; b++) { for (c = 1; c <= 3; c++) { for (d = 1; d <= 3; d++) { for (e = 1; e <= 3; e++) { for (f = 1; f <= 3; f++) { for (g = 1; g <= 3; g++) { for (h = 1; h <= 3; h++) { for (i = 1; i <= 3; i++) { for (j = 1; j <= 3; j++) { if (a + b + c + d + e + f + g + h + i + j == in) { x++; } } } } } } } } } } } cout << x << endl; for (a = 1; a <= 3; a++) { for (b = 1; b <= 3; b++) { for (c = 1; c <= 3; c++) { for (d = 1; d <= 3; d++) { for (e = 1; e <= 3; e++) { for (f = 1; f <= 3; f++) { for (g = 1; g <= 3; g++) { for (h = 1; h <= 3; h++) { for (i = 1; i <= 3; i++) { for (j = 1; j <= 3; j++) { if (a + b + c + d + e + f + g + h + i + j == in) { cout << a << " "; cout << b << " "; cout << c << " "; cout << d << " "; cout << e << " "; cout << f << " "; cout << g << " "; cout << h << " "; cout << i << " "; cout << j << endl; } } } } } } } } } } } }
标签：include 输入格式 输入输出 字典序 方案 cin ace cout color
原文地址：https://www.cnblogs.com/hsjj/p/P2089.html
