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leetcode 300. Longest Increasing Subsequence

时间:2019-08-31 01:16:31      阅读:124      评论:0      收藏:0      [点我收藏+]

标签:lis   lex   solution   input   output   The   seq   example   tor   

Given an unsorted array of integers, find the length of longest increasing subsequence.

Example:

Input: [10,9,2,5,3,7,101,18]
Output: 4 
Explanation: The longest increasing subsequence is [2,3,7,101], therefore the length is 4. 

Note:

  • There may be more than one LIS combination, it is only necessary for you to return the length.
  • Your algorithm should run in O(n2) complexity.

Follow up: Could you improve it to O(n log n) time complexity?

 

分析:求解数组最长递增子序列(严格递增).

思路一:动态规划,时间复杂度:O(n2)。dp[i]表示以下标为i的数字为结尾的最长递增子序列长度。

 1 class Solution {
 2 public:
 3     int lengthOfLIS(vector<int>& nums) {
 4         int len = nums.size();
 5         vector<int> dp(len, 0);
 6         int maxn = 0;
 7         for (int i = 0; i < len; i++) {
 8             dp[i] = 1;
 9             for (int j = 0; j < i; j++) {
10                 if (nums[i] > nums[j])
11                     dp[i] = max(dp[i], dp[j] + 1);
12             }
13             maxn = max(maxn, dp[i]);
14         }
15         return maxn;
16     }
17 };

思路二:动归+二分

 

leetcode 300. Longest Increasing Subsequence

标签:lis   lex   solution   input   output   The   seq   example   tor   

原文地址:https://www.cnblogs.com/qinduanyinghua/p/11437586.html

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