码迷,mamicode.com
首页 > 其他好文 > 详细

两种方法求单链表逆序

时间:2014-10-28 23:56:53      阅读:251      评论:0      收藏:0      [点我收藏+]

标签:blog   http   io   os   ar   sp   div   on   2014   

1 递归,非常easy

代码:

#include<iostream>  

using namespace std;  

typedef struct node{
	int data;
	struct node * pNext;
}Node ,*pNode;

void createNode(pNode & pHead){
	int temp;
	scanf("%d",&temp);
	pNode p,q;
	bool isFirst = true;
	while(temp){
		if(isFirst){
			p=q=pHead=(pNode)malloc(sizeof(Node));
			pHead->data = temp;
			isFirst = false;
		}else{
			q = new Node();
			q->data = temp;
			q->pNext=NULL;
			p->pNext = q;
			p =q;
		}
		scanf("%d",&temp);
	}

}
void print(pNode pHead){
	if(pHead){
		cout<<pHead->data<<" ";
		print(pHead->pNext);
	}else
	return;		
}

void reverse(pNode pcur,pNode & pHead){
	if((NULL == pcur) ||( NULL == pcur->pNext)){
			pHead = pcur;
			return;
	}else{
		pNode pnext = pcur->pNext;
		reverse(pnext,pHead);
		pnext->pNext = pcur;
		pcur->pNext = NULL;
	}
}
int main()  
{  
	pNode pHead = NULL;
	createNode(pHead);
	cout<<"原链表:"<<endl;
	print(pHead);
	cout<<"翻转:"<<endl;
	reverse(pHead,pHead);
	print(pHead);
    return 0;  
}  

执行结果:

bubuko.com,布布扣

2 不是递归,循环:

#include<iostream>  

using namespace std;  

typedef struct node{
	int data;
	struct node * pNext;
}Node ,*pNode;

void createNode(pNode & pHead){
	int temp;
	scanf("%d",&temp);
	pNode p,q;
	bool isFirst = true;
	while(temp){
		if(isFirst){
			p=q=pHead=(pNode)malloc(sizeof(Node));
			pHead->data = temp;
			isFirst = false;
		}else{
			q = new Node();
			q->data = temp;
			q->pNext=NULL;
			p->pNext = q;
			p =q;
		}
		scanf("%d",&temp);
	}

}
void print(pNode pHead){
	if(pHead){
		cout<<pHead->data<<" ";
		print(pHead->pNext);
	}else
	return;		
}

pNode reverse(pNode & pHead){
	if(NULL == pHead || NULL == pHead->pNext){
		return pHead;
	}
	pNode p1,p2,p3;
	p1=pHead;
	p2=pHead->pNext;
	while(p2){
		p3=p2->pNext;
		p2->pNext = p1;
		p1 = p2;
		p2 = p3;
	}
	pHead->pNext = NULL; /*设置链表尾*/
	pHead = p1;  /*调整链表头*/
	return pHead;
}
int main()  
{  
	pNode pHead = NULL;
	createNode(pHead);
	cout<<"原链表:"<<endl;
	print(pHead);
	cout<<"翻转:"<<endl;
	reverse(pHead);
	print(pHead);
    return 0;  
}  

执行结果:

bubuko.com,布布扣


两种方法求单链表逆序

标签:blog   http   io   os   ar   sp   div   on   2014   

原文地址:http://www.cnblogs.com/gcczhongduan/p/4057968.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!