POJ2386 Lake Counting 【DFS】

标签：poj2386

Description

Input

Output

Sample Input

10 12
W........WW.
.WWW.....WWW
....WW...WW.
.........WW.
.........W..
..W......W..
.W.W.....WW.
W.W.W.....W.
.W.W......W.
..W.......W.

Sample Output

3

Hint

Source

睡前水一水。

#include <stdio.h>
#include <string.h>

#define maxn 102

char G[maxn][maxn];
int n, m;
const int mov[][2] = {0, 1, 0, -1, 1, 0, -1, 
				0, 1, -1, -1, 1, 1, 1, -1, -1};

void DFS(int x, int y) {
	G[x][y] = '.';
	int i, j, nx, ny;
	for(i = 0; i < 8; ++i) {
		nx = x + mov[i][0];
		ny = y + mov[i][1];
		if(nx >= 0 && nx < n && ny >= 0 && ny < m && G[nx][ny] == 'W')
			DFS(nx, ny);
	}
}

int main() {
	int i, j, ret;
	while(scanf("%d%d", &n, &m) == 2) {
		for(i = 0; i < n; ++i)
			scanf("%s", G[i]);
		ret = 0;
		for(i = 0; i < n; ++i)
			for(j = 0; j < m; ++j)
				if(G[i][j] == 'W') {
					DFS(i, j);
					++ret;
				}
		printf("%d\n", ret);
	}
	return 0;
}

POJ2386 Lake Counting 【DFS】

标签：poj2386

原文地址：http://blog.csdn.net/chang_mu/article/details/40597237