标签:二分 str ace char return can int names ems
#include <bits/stdc++.h>
using namespace std;
int n,k;
char str[200005];
int a[300];
int maxsum=0;char zm=0;
void return_maxsum_zm(int &maxsum,char &zm)
{
for(int i=‘a‘;i!=‘z‘+1;i++)
{
if(maxsum<a[i])
{
maxsum=a[i];
zm=i;
}
}
}
bool jugde(int mid){
memset(a,0,sizeof(a));
maxsum=0;zm=0;
for(int i=0;i<mid;i++)
{
a[str[i]]+=1;
}
int left=0,right=mid-1;
return_maxsum_zm(maxsum,zm);
//printf("%d-%c\n",maxsum,zm);
while(right<=n)
{
a[str[left]]--;
left++;
right++;
a[str[right]]++;
//printf("%d\n",right);
return_maxsum_zm(maxsum,zm);
//printf("%d-%c\n",maxsum,zm);
if(maxsum>=k){
//printf("%d,ture\n",mid);
return true;
}
}
//printf("%d,false\n",mid);
return false;
}
int main(){
while(~scanf("%d %d",&n,&k)){
getchar();
scanf("%s",str);
int l=k;
int r=n;
int ans=-1;
while(l<=r){
int mid=(l+r)/2;
if(jugde(mid)){
//printf("%d--%d--%d\n",l,mid,r);
ans=mid;
r=mid-1;
}
else{
l=mid+1;
}
}
printf("%d\n",ans);
}
return 0;
}
标签:二分 str ace char return can int names ems
原文地址:https://www.cnblogs.com/MiraculousB/p/12274774.html