11 求2+22+222...的和

 1 a = eval(input(‘请输入一个数字:‘))
 2 n = eval(input(‘请输入次数n:‘))
 3 sum = []
 4 sum2 = 0
 5 s1 = 0
 6 i = 0
 7 while i <= n-1:
 8     s1 =s1+(a*(10**i))
 9     sum.append(s1)
10 
11     i += 1
12 sum1 = [str(i) for i in sum]
13 for j in sum:
14     sum2 += j
15 print(‘+‘.join(sum1),‘=‘,sum2)
16 
17 2）看了大神的写法
18 a =input(‘输入数字>>>:‘)
19 count = int(input(‘几个数字相加>>>:‘))
20 ret = []
21 for i in range(1,count+1):
22     ret.append(int(a*i))
23     print(ret[i-1],end=‘ ‘)
24 print(‘\n结果为:‘,sum(ret))