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把图片用ORC转化成文字,用vim录个宏很容易就可以字母们格式化.....

EBCDIC

A mad scientist found an ancient message from an obsolete IBN System/360 mainframe. He believes that this message contains some very important secret about the Stein‘s Windows Project. The IBN System/360 mainframe uses Extended Binary Coded Decimal Interchange Code (EBCDIC). But his Artificial Intelligence Personal Computer (AIPC) only supports American Standard Code for Information Interchange (ASCII). To read the message, the mad scientist ask you, his assistant, to convert it from EBCDIC to ASCII.
Here is the EBCDIC table.
      
Here is the ASCII table.

C59340D7A2A840C3969587999696

456C2050737920436F6E67726F6F

Hint
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#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <map>

using namespace std;

map<string,int> mp;

string EBCDIC[10000]=
{"NUL","SOH","STX","ETX","  ","HT","  ","DEL","  ","  ","  ","VT","FF","CR","SO","SI",
"DLE","DC1","DC2","DC3","  ","  ","BS","  ","CAN","EM","  ","  ","IFS","IGS","IRS","IUS ITB",
"  ","  ","  ","  ","  ","LF","ETB","ESC","  ","  ","  ","  ","  ","ENQ","ACK","BEL",
"  ","  ","SYN","  ","  ","  ","  ","EOT","  ","  ","  ","  ","DC4","NAK","  ","SUB",
"SP","  ","  ","  ","  ","  ","  ","  ","  ","  ","  ",".","<","(","+","|",
"&","  ","  ","  ","  ","  ","  ","  ","  ","  ","!","$","*",")",";","  ",
"-","/","  ","  ","  ","  ","  ","  ","  ","  ","  ",",","%","_",">","?",
"  ","  ","  ","  ","  ","  ","  ","  ","  ","`",":","#","@","'","=","\"",
"  ","a","b","c","d","e","f","g","h","i","  ","  ","  ","  ","  ","  ",
"  ","j","k","l","m","n","o","p","q","r","  ","  ","  ","  ","  ","  ",
"  ","~","s","t","u","v","w","x","y","z","  ","  ","  ","  ","  ","  ",
"^","  ","  ","  ","  ","  ","  ","  ","  ","  ","[","]","  ","  ","  ","  ",
"{","A","B","C","D","E","F","G","H","I","  ","  ","  ","  ","  ","  ",
"}","J","K","L","M","N","O","P","Q","R","  ","  ","  ","  ","  ","  ",
"\\","  ","S","T","U","V","W","X","Y","Z","  ","  ","  ","  ","  ","  ",
"0","1","2","3","4","5","6","7","8","9","  ","  ","  ","  ","  ","  "};

string ASC[10000]=
{
"NUL","SOH","STX","ETX","EOT","ENQ","ACK","BEL","BS","HT","LF","VT","FF","CR","SO","SI",
"DLE","DC1","DC2","DC3","DC4","NAK","SYN","ETB","CAN","EM","SUB","ESC","IFS","IGS","IRS","IUS ITB",
"SP","!","\"","#","$","%","&","'","(",")","*","+",",","-",".","/",
"0","1","2","3","4","5","6","7","8","9",":",";","<","=",">","?",
"@","A","B","C","D","E","F","G","H","I","J","K","L","M","N","O",
"P","Q","R","S","T","U","V","W","X","Y","Z","[","\\","]","^","_",
"`","a","b","c","d","e","f","g","h","i","j","k","l","m","n","o",
"p","q","r","s","t","u","v","w","x","y","z","{","|","}","~","DEL"
};

void init()
{
    for(int i=0;i<8;i++)
    {
        for(int j=0;j<16;j++)
        {
            mp[ASC[i*16+j]]=i*16+j;
        }
    }
}

int num(char c)
{
    if(c>='0'&&c<='9')
        return c-'0';
    return c-'A'+10;
}

char CHAR(int x)
{
    if(x<=9) return x+'0';
    return x-10+'A';
}

int main()
{
    string READ;
    init();
    while(cin>>READ)
    {
        for(int i=0,sz=READ.size();i<sz;i+=2)
        {
            int c1=num(READ[i]),c2=num(READ[i+1]);
            string ck=EBCDIC[c1*16+c2];
            int id=mp[ck];
            printf("%c%c",CHAR(id/16),CHAR(id%16));
        }
        putchar(10);
    }
    return 0;
}

HDOJ 4690 EBCDIC 模拟

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原文地址：http://blog.csdn.net/ck_boss/article/details/40791263