【数组】977. 有序数组的平方

 1 class Solution {
 2 public:
 3     vector<int> sortedSquares(vector<int>& A) 
 4     {
 5         int len = A.size();
 6         vector<int> ans(len);
 7         int a = 0, b = len - 1, i = b;
 8         while (i >= 0)
 9         {
10             int lef = A[a] * A[a];
11             int rig = A[b] * A[b];
12             if (lef > rig) 
13             {
14                 ans[i] = lef;
15                 a++;
16             }
17             else 
18             {
19                 ans[i] = rig;
20                  b--;
21             }
22             i--;
23         }
24         return ans;
25     }
26 };