标签:length gmpy2 pytho str1 == ESS pre 题目 encrypted
#problem.py
import sys
key = ‘****CENSORED***************‘
flag = ‘TWCTF{*******CENSORED********}‘
if len(key) % 2 == 1:
print("Key Length Error")
sys.exit(1)
n = len(key) / 2
encrypted = ‘‘
for c in flag:
c = ord(c)
for a, b in zip(key[0:n], key[n:2*n]):
c = (ord(a) * c + ord(b)) % 251
encrypted += ‘%02x‘ % c
print encrypted
这道题目和星盟训练赛里最后一道crypto一样
都是化简同余式
str1 = ‘805eed80cbbccb94c36413275780ec94a857dfec8da8ca94a8c313a8ccf9‘.decode(‘hex‘) print str1 import gmpy2 inv = gmpy2.invert(156,251) print inv str2 = ‘‘ for i in str1: str2 += chr(((ord(i)-76)*int(inv))%251) print str2
标签:length gmpy2 pytho str1 == ESS pre 题目 encrypted
原文地址:https://www.cnblogs.com/p201721410013/p/12856584.html