标签：ring red 实现 ace form ash let reduce UNC
//正则
let cash = ‘1234567890‘cash.replace(/\B(?=(\d{3})+(?!\d))/g, ‘,‘);//"1,234,567,890" //非正则的优雅实现 function formatCash(str) { return str.split(‘‘).reverse().reduce((prev, next, index) => { return ((index % 3) ? next : (next + ‘,‘)) + prev }) } formatCash(cash);//"1,234,567,890"标签：ring red 实现 ace form ash let reduce UNC
原文地址：https://www.cnblogs.com/jack123/p/12877008.html
