码迷,mamicode.com
首页 > 其他好文 > 详细

224. Basic Calculator

时间:2020-06-13 19:22:56      阅读:53      评论:0      收藏:0      [点我收藏+]

标签:min   else   tput   sig   ati   div   problems   git   exp   

package LeetCode_224

import java.util.*

/**
 * 224. Basic Calculator
 * https://leetcode.com/problems/basic-calculator/description/
 *
 * Implement a basic calculator to evaluate a simple expression string.
The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces .

Example 1:
Input: "1 + 1"
Output: 2

Example 2:
Input: " 2-1 + 2 "
Output: 3

Example 3:
Input: "(1+(4+5+2)-3)+(6+8)"
Output: 23

Note:
You may assume that the given expression is always valid.
Do not use the eval built-in library function.
 * */
class Solution {

    private val operator = listOf("+", "-")

    fun calculate(s: String): Int {
        val stack = Stack<String>()
        var i = s.length - 1
        while (i >= 0) {
            if (s[i]==‘ ‘){
                i--
                continue
            }
            if (s[i] == ‘)‘ || s[i] == ‘+‘ || s[i] == ‘-‘) {
                stack.push(s[i].toString())
            } else if (s[i] == ‘(‘) {
                val sum = getSum(stack)
                stack.pop()
                stack.push(sum.toString())
            } else {
                val intSB = StringBuilder()
                //pick out the digit, for example:10
                while (i >= 0 && s[i].isDigit()) {
                    intSB.insert(0,s[i--])
                }
                i++//prevent lose some operator, so need go back, for example: 2-1 + 2
                stack.push(intSB.toString())
            }
            i--
        }
        //result = getSum(stack)
        return getSum(stack)
    }

    private fun getSum(stack: Stack<String>): Int {
        var sign = "+"
        var total = 0
        while (stack.isNotEmpty() && stack.peek() != "(" && stack.peek() != ")") {
            if (stack.peek() in operator) {
                sign = stack.pop()
            } else {
                val temp = stack.pop().toInt()
                total += if (sign == "+") temp else -temp
            }
        }
        return total
    }

}

 

224. Basic Calculator

标签:min   else   tput   sig   ati   div   problems   git   exp   

原文地址:https://www.cnblogs.com/johnnyzhao/p/13121345.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!