PTA 乙级 1001 害死人不偿命的(3n+1)猜想 (15分)

 1 #include<stdio.h>
 2 
 3 int main(){
 4     int n = 0;
 5     int num = 0;
 6     //printf("请输入一个不超过1000的正整数：");
 7     scanf("%d", &num);
 8     while(num != 1){
 9         if(num%2 == 0){
10             num = num / 2;
11             n++;
12         }else{
13             num = (3*num + 1) / 2;
14         //    printf("%d\n",num)]; 
15             n++;
16         }
17     }
18     printf("%d\n", n);
19     return 0;
20     
21 }