标签:max names may pat include ons oar boa put
【原题】
Description
Input
Output
Sample Input
4 4 *.*. .*** ***. ..*.
Sample Output
4
Hint
#include <algorithm>
#include <cmath>
#include <cstdio>
#include <cstring>
#include <list>
#include <map>
#include <iostream>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <vector>
#include <iomanip>
#define LL long long
#define inf 0x3f3f3f3f
#define INF 0x3f3f3f3f3f3f
#define PI 3.1415926535898
#define F first
#define S second
#define lson rt << 1
#define rson rt << 1 | 1
using namespace std;
const int maxn = 57;
const int maxm = 2e5 + 7;
int n, m;
char mp[maxn][maxn];
int r[maxn][maxn], c[maxn][maxn];
int cnt = 0, rnum;
vector <int> G[6000];
int vis[2 * maxn * maxn], link[2 * maxn * maxn];
bool dfs(int u)
{
for (int i = 0; i < G[u].size(); i++)
{
int v = G[u][i];
if (!vis[v])
{
vis[v] = 1;
if (!link[v] || dfs(link[v]))
{
link[v] = u;
return true;
}
}
}
return false;
}
int max_match()
{
memset(link, 0, sizeof(link));
int ans = 0;
for (int i = 1; i <= rnum; i++)
{
memset(vis, 0, sizeof(vis));
if (dfs(i)) ans++;
}
return ans;
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);
cin >> n >> m;
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= m; j++)
{
cin >> mp[i][j];
if (mp[i][j] == ‘*‘)
{
if (mp[i - 1][j] == ‘*‘) r[i][j] = r[i - 1][j];
else r[i][j] = ++cnt;
}
}
}
rnum = cnt;
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= m; j++)
{
if (mp[i][j] == ‘*‘)
{
if (mp[i][j - 1] == ‘*‘) c[i][j] = c[i][j - 1];
else c[i][j] = ++cnt;
G[r[i][j]].push_back(c[i][j]);
}
}
}
cout << max_match() << endl;
}
标签:max names may pat include ons oar boa put
原文地址:https://www.cnblogs.com/hfcdyp/p/13374018.html