标签：net script letter turn rtt with ppi system condition
InputThere is only one case. First there is an integer P (1<=P<=10000)representing the number of the merchanidse names in the repository. The next P lines each contain a string (it‘s length isn‘t beyond 20,and all the letters are lowercase).Then there is an integer Q(1<=Q<=100000) representing the number of the queries. The next Q lines each contains a string(the same limitation as foregoing descriptions) as the searching condition.OutputFor each query, you just output the number of the merchandises, whose names contain the search string as their substrings.Sample Input
20 ad ae af ag ah ai aj ak al ads add ade adf adg adh adi adj adk adl aes 5 b a d ad s
Sample Output
0 20 11 11 2
1 #include <cstdio> 2 #include <cstring> 3 using namespace std; 4 const int N = 1e6 + 5; 5 int trie[N][26], cnt[N], id[N], L; 6 7 void insertTrie(char s[], int iid) 8 { 9 int r = 0, i = 0, j; 10 while(s[i]) 11 { 12 j = s[i++] - ‘a‘; 13 if(!trie[r][j]) 14 trie[r][j] = L++; 15 r = trie[r][j]; 16 if(id[r] != iid) ++cnt[r]; 17 id[r] = iid; 18 } 19 } 20 int searchTrie(char s[]) 21 { 22 int r = 0, i = 0, j; 23 while(s[i]) 24 { 25 j = s[i++] - ‘a‘; 26 if(!trie[r][j]) 27 return 0; 28 r = trie[r][j]; 29 } 30 return cnt[r]; 31 } 32 33 int main() 34 { 35 L = 1; 36 char s[30]; 37 int p, q; 38 scanf("%d", &p); 39 for(int i = 1; i <= p; ++i) 40 { 41 scanf("%s", s); 42 for(int j = 0; s[j]; ++j) 43 insertTrie(s + j, i); 44 } 45 scanf("%d", &q); 46 while(q--) 47 { 48 scanf("%s", s); 49 printf("%d\n", searchTrie(s)); 50 } 51 return 0; 52 }
标签：net script letter turn rtt with ppi system condition
原文地址：https://www.cnblogs.com/linda-/p/13383000.html
