标签:邻接 jks std stream ret iostream 初始化 dijkstra ace
#include<stdio.h>
#include<iostream>
using namespace std;
const int maxn=1010;
const int INF=1000000000;
int n,m,c1,c2;
int G[maxn][maxn],d[maxn];
int weight[maxn],w[maxn];
int num[maxn];
int vis[maxn];
void dijkstra(int s){
fill(d,d+maxn,INF);
fill(w,w+maxn,0);
fill(num,num+maxn,0);
d[s]=0;
w[s]=weight[s];
num[s]=1;
for(int i=0;i<n;i++){
int u=-1,min=INF;
for(int j=0;j<n;j++){
if(vis[j]==0&&d[j]<min){
u=j;
min=d[j];
}
}
if(u==-1)return;
vis[u]=1;
for(int v=0;v<n;v++){
if(vis[v]==0&&G[u][v]!=INF){
if(d[u]+G[u][v]<d[v]){
d[v]=d[u]+G[u][v];
w[v]=w[u]+weight[v];
num[v]=num[u];
}
else if(d[u]+G[u][v]==d[v]){
if(w[v]<w[u]+weight[v]){
w[v]=w[u]+weight[v];
}
num[v]+=num[u];
}
}
}
}
}
int main()
{
scanf("%d %d %d %d",&n,&m,&c1,&c2);
for(int i=0;i<n;i++){
scanf("%d",&weight[i]);
}
int a,b,c;
fill(G[0],G[0]+maxn*maxn,INF); //这里的初始化图的方式需要注意
for(int i=0;i<m;i++){
scanf("%d %d %d",&a,&b,&c);
G[a][b]=c;
G[b][a]=G[a][b]; //2、5测试点一直错的原因 邻接矩阵的存储是关于斜对角线对称的
}
dijkstra(c1);
printf("%d %d",num[c2],w[c2]);
}
标签:邻接 jks std stream ret iostream 初始化 dijkstra ace
原文地址:https://www.cnblogs.com/1012wenquan66/p/13660294.html