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102. 二叉树的层序遍历

时间:2020-11-26 14:41:52      阅读:8      评论:0      收藏:0      [点我收藏+]

标签:queue   solution   nat   lan   log   data   sizeof   栈和队列   不能   

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     struct TreeNode *left;
 *     struct TreeNode *right;
 * };
 */


/**
 * Return an array of arrays of size *returnSize.
 * The sizes of the arrays are returned as *returnColumnSizes array.
 * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().
 */
 #define MAXNODE 5000
 struct TreeNode  *treequeue[MAXNODE];
 
int** levelOrder(struct TreeNode* root, int* returnSize, int** returnColumnSizes){
    *returnSize=0;
    if(root==NULL){
        * returnSize=0;
        return NULL;
    }
    //二维数组分配内存
    int **ret=(int **)malloc(sizeof(int *)*MAXNODE);
    //不能够申请这么大空间,后面使用的时候按照需要申请,否则容易超时
    //for(int i=0;i<MAXNODE;i++){
    //    ret[i]=(int *)malloc(sizeof(int)*MAXNODE);
    //}
    //出参数分配内存
    *returnColumnSizes = (int *)malloc(sizeof(int) * MAXNODE);//注意这块也要分配内存

    int start=0;
    int end=0;
    
    treequeue[end++]=root;
    struct TreeNode  *tmptree=NULL;

    while(start<end){
        //当前层节点数
        (* returnColumnSizes)[*returnSize]=end-start;
        // 此处已经有长度可以在这里进行申请内存,减少时间使用
        ret[*returnSize] = (int *)malloc(sizeof(int) * (end-start));
        for(int i=0;i<(*returnColumnSizes)[*returnSize];i++){
            tmptree=treequeue[start];
            ret[*returnSize][i]=tmptree->val;
            if(tmptree->left){
                treequeue[end++]=tmptree->left;
            }
            if(tmptree->right){
                treequeue[end++]=tmptree->right;
            }
            start++;
        }
        (*returnSize)++;
    }
    return ret;
}

  

给你一个二叉树,请你返回其按 层序遍历 得到的节点值。 (即逐层地,从左到右访问所有节点)。

 

示例:
二叉树:[3,9,20,null,null,15,7],

    3
   /   9  20
    /     15   7

返回其层次遍历结果:

[
  [3],
  [9,20],
  [15,7]
]


总结:

C语言实现:栈和队列
102题:
优秀代码:
https://leetcode-cn.com/problems/binary-tree-level-order-traversal/solution/102-er-cha-shu-de-ceng-xu-bian-li-cyu-yan-bfs-by-x/
bfs:
https://leetcode-cn.com/problems/binary-tree-level-order-traversal/solution/cyu-yan-zhen-de-zao-bu-qi-lun-zi-liao-shun-xu-dui-/
https://leetcode-cn.com/problems/binary-tree-level-order-traversal/solution/cti-jie-bfs-shu-zu-mo-ni-dui-lie-by-justdoitno1/

https://leetcode-cn.com/problems/binary-tree-level-order-traversal/solution/xiao-hao-nei-cun-jiao-da-by-lang-dao/只实现初始化和pop push操作

https://leetcode-cn.com/problems/binary-tree-level-order-traversal/solution/c-yu-yan-4-ms-89-mb-by-chen-xiang-yin/使用大数组替代队列
申请空间数组
https://leetcode-cn.com/problems/binary-tree-level-order-traversal/solution/102-er-cha-shu-de-ceng-xu-bian-li-cyu-yan-bfs-by-x/

dfs:https://leetcode-cn.com/problems/binary-tree-level-order-traversal/solution/cyu-yan-shen-du-you-xian-sou-suo-by-jing-shui-li-2/

 

c语言实现队列:
https://mp.weixin.qq.com/s?src=11&timestamp=1606011440&ver=2721&signature=OJj6qdyHzyY9zVf6zzunnMeLMkOo6RAGYzj8WbeigLasQUzmxOG*m13VqbB27cUFfta8SGzlbxCf6U7nxpYMy028qDJLemKXOfmKMyR*37IUkRXbNc45M1bJQ889BmVR&new=1
https://blog.csdn.net/weixin_41143631/article/details/81675177

C语言实现栈:
https://zhuanlan.zhihu.com/p/90582016

本体主要考察:
1、int** returnColumnSizes返回方式
2、bfs使用方法;
3、申请内存尽量按照需要使用否则容易出现超时
4、二维指针的返回值使用

5、dfs要使用stack,bfs要使用队列

102. 二叉树的层序遍历

标签:queue   solution   nat   lan   log   data   sizeof   栈和队列   不能   

原文地址:https://www.cnblogs.com/cheshl/p/14022190.html

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