标签:搜索
| Time Limit: 1000MS | Memory Limit: 65536K | |
| Total Submissions: 17007 | Accepted: 6620 |
Description
Input
Output
Escaped in x minute(s).
Trapped!
Sample Input
3 4 5 S.... .###. .##.. ###.# ##### ##### ##.## ##... ##### ##### #.### ####E 1 3 3 S## #E# ### 0 0 0
3维地图给起点和终点搜最短路。。刷dfs专题刷出来这玩意也是醉了。。
BFS暴搜
#include <algorithm>
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <string>
#include <cctype>
#include <vector>
#include <cstdio>
#include <cmath>
#include <queue>
#include <stack>
#include <map>
#include <set>
#define ll long long
#define maxn 360
#define pp pair<int,int>
#define INF 0x3f3f3f3f
#define max(x,y) ( ((x) > (y)) ? (x) : (y) )
#define min(x,y) ( ((x) > (y)) ? (y) : (x) )
using namespace std;
int n,m,sx,sy,sz,A,B,C;
bool vis[105][105][105];
char ma[105][105][105];
struct node
{
int x,y,z,step;
};
int mv[6][3]={{0,0,1},{0,0,-1},{1,0,0},{-1,0,0},{0,1,0},{0,-1,0}};
void bfs()
{
queue <node> Q;
node t;
t.x=sx;t.y=sy;t.z=sz;t.step=0;
vis[sx][sy][sz]=1;
Q.push(t);
while(!Q.empty())
{
node f=Q.front();Q.pop();
if(ma[f.x][f.y][f.z]=='E')
{
printf("Escaped in %d minute(s).\n",f.step);
return ;
}
for(int i=0;i<6;i++)
{
t.x=f.x+mv[i][0];
t.y=f.y+mv[i][1];
t.z=f.z+mv[i][2];
if(0<=t.x&&t.x<A&&0<=t.y&&t.y<B&&0<=t.z&&t.z<C&&!vis[t.x][t.y][t.z]&&ma[t.x][t.y][t.z]!='#')
{
vis[t.x][t.y][t.z]=1;
t.step=f.step+1;
Q.push(t);
}
}
}
puts("Trapped!");
}
int main()
{
while(scanf("%d%d%d",&A,&B,&C)!=EOF)
{
if(!A&&!B&&!C)break;
memset(vis,0,sizeof(vis));
for(int i=0;i<A;i++)
for(int j=0;j<B;j++)
scanf("%s",ma[i][j]);
for(int i=0;i<A;i++)
for(int j=0;j<B;j++)
for(int k=0;k<C;k++)
if(ma[i][j][k]=='S')
{
sx=i;sy=j;sz=k;
break;
}
bfs();
}
return 0;
}标签:搜索
原文地址:http://blog.csdn.net/qq_16255321/article/details/41287177