谁获得最高奖学金

1
4
YaoLin 87 82 Y N 0
ChenRuiyi 88 78 N Y 1
LiXin 92 88 N N 0
ZhangQin 83 87 Y N 1

ChenRuiyi
9000
28700

解题思路：

对于这种每个研究对象有多个数据的题目，用结构体无疑是最好的选择。对结构体的操作格式为是s[i].name，读取数据应该注意空格scanf("%s %d %d %c %c %d",s[i].name,......)

程序代码：

# include <stdio.h>
struct StudentI{
	char name[20];
	int Qmpjcj;
	int Bjpycj;
	char Gb;
	char Xb;
	int Lw;
	int Jxj;
};
int main()
{
	StudentI s[100];
	int N,X;
	scanf("%d",&N);
	while(N--){
		int i,Max=0,Wz = 0,Sum = 0;
		scanf("%d",&X);
		for(i = 0; i < X; ++i){
			scanf("%s %d %d %c %c %d",s[i].name,&s[i].Qmpjcj,&s[i].Bjpycj,&s[i].Gb,&s[i].Xb,&s[i].Lw);
			s[i].Jxj = 0;
		}
		for(i = 0; i < X; ++i){
			if(s[i].Qmpjcj > 80 && s[i].Lw >= 1)
				s[i].Jxj += 8000;
			if(s[i].Qmpjcj > 85 && s[i].Bjpycj > 80)
				s[i].Jxj += 4000;
			if(s[i].Qmpjcj > 90)
				s[i].Jxj += 2000;
			if(s[i].Qmpjcj > 85 && s[i].Xb == 'Y')
				s[i].Jxj += 1000;
			if(s[i].Bjpycj > 80 && s[i].Gb == 'Y')
				s[i].Jxj += 850;
			Sum += s[i].Jxj; 
			if(Max < s[i].Jxj){
				Max = s[i].Jxj;
				Wz = i;
			}
		}
		printf("%s\n%d\n%d\n",s[Wz].name,s[Wz].Jxj,Sum);

	}
	
	return 0;
}