标签：uva

CD

You have a long drive by car ahead. You have a tape recorder, but unfortunately your best music is on CDs. You need to have it on tapes so the problem to solve is: you have a tape N minutes long. How to choose tracks from CD to get most out of tape space and have as short unused space as possible.

Assumptions:

• number of tracks on the CD. does not exceed 20
• no track is longer than N minutes
• tracks do not repeat
• length of each track is expressed as an integer number
• N is also integer

Program should find the set of tracks which fills the tape best and print it in the same sequence as the tracks are stored on the CD

Input 

Output 

Sample Input 

5 3 1 3 4
10 4 9 8 4 2
20 4 10 5 7 4
90 8 10 23 1 2 3 4 5 7
45 8 4 10 44 43 12 9 8 2

Sample Output 

1 4 sum:5
8 2 sum:10
10 5 4 sum:19
10 23 1 2 3 4 5 7 sum:55
4 10 12 9 8 2 sum:45

直接枚举所有状态

#include <stdio.h>
#include <string.h>
using namespace std;
const int inf=1<<30;
#define max(a,b) (a>b?a:b)
#define ll long long

ll sum,n,a[25],tem,maxn,flag;

int main()
{
    ll i,j;
   while(~scanf("%lld%lld",&sum,&n))
    {
        maxn = -inf;
        for(i=1; i<=n; i++)
            scanf("%lld",&a[i]);
        tem = 1<<n;
        for(i = 1; i<tem; i++)
        {
            ll t=i,k=1,s=0;
            while(t)
            {
                ll r = t%2;
                t/=2;
                if(r)
                {
                    s+=a[k];
                }
                k++;
            }
            if(s<=sum && s>=maxn)
            {
                maxn = max(maxn,s);
                flag = i;
            }
        }
        ll k = 1;
        while(flag)
        {
            ll r = flag%2;
            flag/=2;
            if(r)
            {
                printf("%lld ",a[k]);
            }
            k++;
        }
        printf("sum:%lld\n",maxn);
    }

    return 0;
}

UVA624:CD

标签：uva

原文地址：http://blog.csdn.net/libin56842/article/details/41523287