2 5 6 -1 5 4 -7 7 0 6 -1 1 -6 7 -5
Case 1: 14 1 4 Case 2: 7 1 6
#include<stdio.h>
main()
{
int n, i, a[100002], b, j, s, m, k;
long max, sum;
while ( scanf ( "%d", &n ) != EOF )
{
for ( j = 1; j <= n; j++ )
{
scanf ( "%d", &m );
for ( i = 0; i < m; i++ )
scanf ( "%d", &a[i] );
sum = 0;
b = 1;
max = -1001;
for ( i = 0; i < m; i++ )
{
sum += a[i];
if ( sum > max )
{
max = sum;
k = b;
s = i + 1;
}
if ( sum < 0 )
{
sum = 0;
b = i + 2;
}
}
if ( j != n )
printf ( "Case %d:\n%ld %d %d\n\n", j, max, k, s );
else
printf ( "Case %d:\n%ld %d %d\n", j, max, k, s );
}
}
}
原文地址:http://blog.csdn.net/acm_baihuzi/article/details/41677223