标签:java leetcode dynamic programming string
Given a string S and a string T, count the number of distinct subsequences of T in S.
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ACE" is
a subsequence of "ABCDE" while "AEC" is
not).
Here is an example:
S = "rabbbit", T = "rabbit"
Return 3.
如果S[ i ] == T[ j ] 那么f[i][j] = f[i - 1][j] + f[i - 1][j - 1]
反之f[i][j] = f[i - 1][j]
要注意初始化
public class Solution {
public int numDistinct(String S,String T) {
if(S.length()<1||T.length()<1||S.length()<T.length()) return 0;
int f[][] = new int[S.length()][T.length()];
int in = 0;
for(int i=0;i<S.length();i++){
if(S.charAt(i)==T.charAt(0)) in++;
f[i][0] = in;
}
for(int j=1;j<T.length();j++){
for(int i=j;i<S.length();i++){
if(S.charAt(i)==T.charAt(j)){
f[i][j] = f[i-1][j]+f[i-1][j-1];
}else{
f[i][j] = f[i-1][j];
}
}
}
return f[S.length()-1][T.length()-1];
}
}
[LeetCode]Distinct Subsequences
标签:java leetcode dynamic programming string
原文地址:http://blog.csdn.net/guorudi/article/details/41810671