九度OJ 1079 手机键盘 （模拟）

上个手键盘图

我的思路是：把每个字母都映射到相应的按键上，在每个按键上根据顺序又有区分，m[‘a‘]=10,m[‘b‘]=11,m[‘c‘]=12,m[‘d‘]=20.......

这样hash表的值只要十位相同，就表示在一个按键上，个位上的数字加一就是要按得次数

#include<stdio.h>
#include<string.h>
int ans;
char s[120];
char m[256];
void init()
{
    memset(m,0,sizeof(m));
    m['a']=m['b']=m['c']=10;
    m['b']+=1;
    m['c']+=2;
    m['d']=m['e']=m['f']=20;
    m['e']+=1;
    m['f']+=2;
    m['g']=m['h']=m['i']=30;
    m['h']+=1;
    m['i']+=2;
    m['j']=m['k']=m['l']=40;
    m['k']+=1;
    m['l']+=2;
    m['m']=m['n']=m['o']=50;
    m['n']+=1;
    m['o']+=2;
    m['p']=m['q']=m['r']=m['s']=60;
    m['q']+=1;
    m['r']+=2;
    m['s']+=3;
    m['t']=m['u']=m['v']=70;
    m['u']+=1;
    m['v']+=2;
    m['w']=m['x']=m['y']=m['z']=80;
    m['x']+=1;
    m['y']+=2;
    m['z']+=3;
}
int main(int argc, char *argv[])
{
   // freopen("1079.in", "r", stdin);
    init();
    while(~scanf("%s",s))
    {
        ans=0;
        for(int i=0;i<strlen(s);++i)
        {
            if(i==0){
                ans+=(m[s[i]]%10+1);
            }
            else if(m[s[i]]/10==m[s[i-1]]/10){
                ans+=2;
                ans+=(m[s[i]]%10+1);
            }
            else
            {
                ans+=(m[s[i]]%10+1);
            }
        }
        printf("%d\n",ans);
    }
    return 0;
}
 
/**************************************************************
    Problem: 1079
    User: kirchhoff
    Language: C
    Result: Accepted
    Time:10 ms
    Memory:912 kb
****************************************************************/