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5
Huge input, scanf is recommended.
题目大意:给你一个图,求连接所有点的最短路径。
思路:Prim算法求图的最小生成树,模板题。
# include<stdio.h>
# include<string.h>
const int INF = 0xffffff0;
const int MAXN = 110;
int map[MAXN][MAXN],low[MAXN],vis[MAXN];
int n;
int prim()
{
    int i,j,pos,Min,result = 0;
    memset(vis,0,sizeof(vis));
    vis[1] = 1;
    pos = 1;
    for(i = 1; i <= n; i++)
        if(i != pos)
            low[i] = map[pos][i];
    for(i = 1; i < n; i++)
    {
        Min = INF;
        for(j = 1; j <= n; j++)
        {
            if(vis[j]==0 && Min > low[j])
            {
                Min = low[j];
                pos = j;
            }
        }
        result += Min;
        vis[pos] = 1;
        for(j = 1; j <= n; j++)
        {
            if(vis[j]==0 && low[j] > map[pos][j])
            {
                low[j] = map[pos][j];
            }
        }
    }
    return result;
}
int main()
{
    int x,y,d;
    while(~scanf("%d",&n) && n)
    {
        memset(map,INF,sizeof(map));
        for(int i = 1; i <= n*(n-1)/2; i++)
        {
            scanf("%d%d%d",&x,&y,&d);
            map[x][y] = map[y][x] = d;
        }
        printf("%d\n",prim());
    }
    return 0;
}
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原文地址:http://blog.csdn.net/lianai911/article/details/42111349