Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
利用快慢指针
/**
* Definition for singly-linked list.
* class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public boolean hasCycle(ListNode head) {
if(head==null) return false;
ListNode slow = head;
ListNode fast = head.next;
while(slow!=null&&fast!=null&&fast.next!=null){
if(slow ==fast) return true;
slow = slow.next;
fast = fast.next.next;
}
return false;
}
}原文地址:http://blog.csdn.net/guorudi/article/details/42242625