Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
For example,
Given 1->2->3->3->4->4->5, return 1->2->5.
Given 1->1->1->2->3, return 2->3.
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution
{
public:
ListNode *deleteDuplicates(ListNode *head)
{
if(head==NULL || head->next==NULL)
return head;
ListNode* save = head;
int flag = head->next->val;
ListNode* pre = head->next;
ListNode* end = pre->next;
while(end != NULL)
{
if(pre->val != end->val)
{
if(pre->next == end)
{
save = pre;
pre = end;
}
else
{
save->next = end;
pre = end;
}
}
end = end->next;
}
if(pre->next != NULL)
save->next = NULL;
while(head!=NULL && head->next!=NULL)
{
if(head->val!=head->next->val)
break;
head = head->next;
}
if(head!=NULL && head->val == flag)
head = head->next;
return head;
}
};LeetCode--Remove Duplicates from Sorted List II
原文地址:http://blog.csdn.net/shaya118/article/details/42677161