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Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others)
Total Submission(s): 2759 Accepted Submission(s): 1420
#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstdlib>
#include<string>
#include<algorithm>
#include<cstring>
using namespace std;
int a[110],b[110],dp[100010];
int n,m;
int main()
{
while(scanf("%d",&n)!=EOF)
{
memset(dp,0,sizeof(dp));
for(int i=1;i<=n;i++)
scanf("%d%d",&a[i],&b[i]);
scanf("%d",&m);
for(int i=1;i<=n;i++)
{
for(int j=b[i];j<=m;j++)
dp[j]=max(dp[j],dp[j-b[i]]+a[i]);
}
printf("%d\n",dp[m]);
}
return 0;
}
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原文地址:http://www.cnblogs.com/a972290869/p/4231274.html