200.00 3 2 A:23.50 B:100.00 1 C:650.00 3 A:59.99 A:120.00 X:10.00 1200.00 2 2 B:600.00 A:400.00 1 C:200.50 1200.50 3 2 B:600.00 A:400.00 1 C:200.50 1 A:100.00 100.00 0
123.50 1000.00 1200.50
#include<iostream>
#include<cstring>
#include<cstdio>
using namespace std;
int v[35],dp[3000000+5];
int main(){
double P,n;
while(cin>>P>>n && n){
P*=100;
int i,j,m,a,b,c,flag;
for(i=1;i<=n;i++){
double p;
char ch,cc;
cin>>m;
a=b=c=flag=0;
for(j=1;j<=m;j++){
scanf("%c%c:%lf",&cc,&ch,&p);
p*=100;
if(ch=='A') a+=p;
else if(ch=='B') b+=p;
else if(ch=='C') c+=p;
else flag=1;
}
if(!flag&&a+b+c<=100000&&a<=60000&&b<=60000&&c<=60000)
v[i]=a+b+c;
else v[i]=P+1;
}
memset(dp,0,sizeof dp);
for(i=1;i<=n;i++)
for(j=P;j>=v[i];j--)
dp[j]=max(dp[j],dp[j-v[i]]+v[i]);
printf("%.2lf\n",dp[(int)P]/100.0);
}
return 0;
}
原文地址:http://blog.csdn.net/hyccfy/article/details/42833761