10 1 2 3 4 5 6 7 8 9 10 5 0 1 10 1 1 10 1 1 5 0 5 8 1 4 8
Case #1: 19 7 6
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<string>
#include<algorithm>
#include<cstdlib>
#include<set>
#include<queue>
#include<stack>
#include<vector>
#include<map>
#define N 100010
#define Mod 10000007
#define lson l,mid,idx<<1
#define rson mid+1,r,idx<<1|1
#define lc idx<<1
#define rc idx<<1|1
const double EPS = 1e-11;
const double PI = acos ( -1.0 );
const double E = 2.718281828;
typedef long long ll;
const int INF = 1000010;
using namespace std;
struct node
{
    __int64 sum;
    int op;//1:区间全为1 0:不全为1
} tree[N<<2];
int n,m;
void push_up(int idx)
{
    tree[idx].sum=tree[lc].sum+tree[rc].sum;
    tree[idx].op=(tree[lc].op==1&&tree[rc].op==1);
}
void build(int l,int r,int idx)
{
    tree[idx].op=0;
    if(l==r)
    {
        scanf("%I64d",&tree[idx].sum);
        return;
    }
    int mid=(l+r)>>1;
    build(lson);
    build(rson);
    push_up(idx);
}
void update(int l,int r,int idx,int x,int y)
{
    if(tree[idx].op==1)
        return;
    if(l==r)
    {
        tree[idx].sum=sqrt(double(tree[idx].sum));
        if(tree[idx].sum==1)
            tree[idx].op=1;
        return;
    }
    int mid=(l+r)>>1;
    if(x<=mid)
        update(lson,x,y);
    if(y>mid)
        update(rson,x,y);
    push_up(idx);
}
__int64 query(int l,int r,int idx,int x,int y)
{
    if(x<=l&&r<=y)
        return tree[idx].sum;
    __int64 ans=0;
    int mid=(l+r)>>1;
    if(x<=mid)
        ans+=query(lson,x,y);
    if(y>mid)
        ans+=query(rson,x,y);
    return ans;
}
int main()
{
    //freopen("in.txt","r",stdin);
    int ca=1;
    while(~scanf("%d",&n))
    {
        build(1,n,1);
        scanf("%d",&m);
        printf("Case #%d:\n",ca++);
        int x,y,op;
        while(m--)
        {
            scanf("%d%d%d",&op,&x,&y);
            if(x>y)
                swap(x,y);
            if(op)
                printf("%I64d\n",query(1,n,1,x,y));
            else
                update(1,n,1,x,y);
        }
        printf("\n");
    }
    return 0;
}
Hdu 4027 Can you answer these queries?(线段树)
原文地址:http://blog.csdn.net/acm_baihuzi/article/details/43062983