题目如下：
Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.
Input Specification:
Each input file contains one test case. Each case occupies one line which contains an N (<= 10100).
Output Specification:
For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.
Sample Input:12345Sample Output:
one five
#include<iostream>
#include<string>
#include<sstream>
#include<vector>
using namespace std;
int sumdigits(string data);
template<class out, class in>
out convert(in a);
int main()
{
string data;
string digit[] = {"zero","one","two","three","four","five","six","seven","eight","nine"};
string temp;
while(cin>>data)
{
temp = convert<string>(sumdigits(data));
for(int i = 0; i < temp.length(); i++)
{
cout<<digit[convert<int>(temp[i])];
if (i != temp.length() - 1)
cout<<" ";
}
cout<<endl;
}
return 0;
}
int sumdigits(string data)
{
if ("" == data)
return 0;
int sum = 0;
sum += convert<int>(data[data.length()-1]);
sum += sumdigits(data.substr(0, data.length() - 1));
return sum;
}
template<class out, class in>
out convert(in a)
{
stringstream temp;
temp<<a;
out b;
temp>>b;
return b;
}原文地址：http://blog.csdn.net/u011233383/article/details/43204823
