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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 12771 Accepted Submission(s): 3290
3 aaa bbb ccc 2 aaabbbccc bbaacc
web 1: 1 2 3 total: 1
入门2,从给出的串中找出现的病毒串的序号,输出,防止多次统计,所以用vis记录是否出现过第i病毒。
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <queue>
using namespace std ;
struct node
{
int flag ;
node *next[100] , *fail ;
};
char str[11000] , s[210] ;
queue <node*> que ;
int vis[600] ;
node *newnode()
{
node *p = new node ;
p->flag = 0 ;
p->fail = NULL ;
int i ;
for(i = 0 ; i < 100 ; i++)
p->next[i] = NULL ;
return p ;
}
void settree(char *s,node *rt,int temp)
{
int i , k , l = strlen(s) ;
node *p = rt ;
for(i = 0 ; i < l ; i++)
{
k = s[i] - 32 ;
if( p->next[k] == NULL )
p->next[k] = newnode() ;
p = p->next[k] ;
}
p->flag = temp ;
}
void setfail(node *rt)
{
int i , j , k ;
node *p , *temp ;
rt->fail = NULL;
while( !que.empty() ) que.pop() ;
que.push(rt) ;
while( !que.empty() )
{
p = que.front() ;
que.pop() ;
for(i = 0 ; i < 100 ; i++)
{
if( p->next[i] )
{
temp = p->fail ;
while( temp && !temp->next[i] )
temp = temp->fail ;
p->next[i]->fail = temp ? temp->next[i] : rt ;
que.push(p->next[i]) ;
}
else
p->next[i] = p == rt ? rt : p->fail->next[i] ;
}
}
}
int query(char *str,node *rt)
{
int i , k , l = strlen(str) ;
int flag = 0 ;
node *p = rt , *temp ;
for(i = 0 ; i < l ; i++)
{
k = str[i] - 32 ;
p = p->next[k] ;
temp = p ;
while( temp && temp->flag )
{
if( vis[ temp->flag ] ) break ;
vis[ temp->flag ] = 1 ;
flag = 1 ;
temp = temp->fail ;
}
}
return flag ;
}
int main()
{
int n , m , i , j , num ;
node *rt ;
while( scanf("%d", &n) != EOF)
{
rt = newnode() ;
for(i = 1 ; i <= n ; i++)
{
scanf("%s", s) ;
settree(s,rt,i) ;
}
setfail(rt) ;
scanf("%d", &m) ;
num = 0 ;
for(i = 1 ; i <= m ; i++)
{
memset(vis,0,sizeof(vis)) ;
scanf("%s", str) ;
if( query(str,rt) )
{
num++ ;
printf("web %d:", i) ;
for(j = 0 ; j < 600 ; j++)
if( vis[j] )
printf(" %d", j) ;
printf("\n") ;
}
}
printf("total: %d\n", num) ;
}
return 0;
}
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原文地址:http://blog.csdn.net/winddreams/article/details/43410235