J - Candy Sharing Game(模拟题）

A number of students sit in a circle facing their teacher in the center. Each student initially has an even number of pieces of candy. When the teacher blows a whistle, each student simultaneously gives half of his or her candy to the neighbor on the right. Any student, who ends up with an odd number of pieces of candy, is given another piece by the teacher. The game ends when all students have the same number of pieces of candy.       
Write a program which determines the number of times the teacher blows the whistle and the final number of pieces of candy for each student from the amount of candy each child starts with.      

The input may describe more than one game. For each game, the input begins with the number N of students, followed by N (even) candy counts for the children counter-clockwise around the circle. The input ends with a student count of 0. Each input number is on a line by itself.      

For each game, output the number of rounds of the game followed by the amount of candy each child ends up with, both on one line.      

注意我划上红线的地方：

1.首先每个学生起初都含有的是偶数个数的糖。

2.当每次老师吹哨时，每个同学同时给出一半他现在手中所含有的糖给他的右边的那位同学（注意，这句话的意思是说，每个人都是先把糖给出去的然后再去接受别人的糖，并不是像击鼓传花那样，一个人给出去，然后第二个人接受，然后再以他现在所含有的糖数的1/2再给第三个人。而是把起始的糖数分给右边的人，要不然这个循环永远都不会结束。）

3.当每个学生得到糖数结束后，如果是奇数个的糖，那么老师就会再分给他一颗糖，凑成偶数。

 

#include<stdio.h>
#include<string.h>
int main(){
	int n,i,j,k;
	int a[1000];
	while(scanf("%d",&n)!=EOF){
		if(n==0) break;
		for(i=1;i<=n;i++)
			scanf("%d",&a[i]);
		int num=0,f=1,temp;
		while(1){
			f=1;
			for(i=1;i<n;i++){
				if(a[i]!=a[i+1])  {f=0; break;}
			}
			if(f) break;
			//要注意对a[1]的判断，因为它是特别的，要优先保存a[n],防止它变掉； 
			temp=a[n]/2;
			for(i=n;i>1;i--){
				a[i]=a[i]/2;
				a[i]+=a[i-1]/2;
				if(a[i]%2) a[i]++;
			}
			a[1]=a[1]/2;
			a[1]+=temp;
			//如果要对学生手中是否含有的糖数是奇数个时，用for一遍是个好方法，毕竟简单好想。 
			for(i=1;i<=n;i++){
				if(a[i]%2) a[i]++;
			}
			num++;		
		}
		printf("%d %d\n",num,a[1]);
	}
}