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//Notes:
1、每个结果最后有2个\n\n
2、‘A‘->‘A‘ ‘B‘->‘ ‘ ‘E‘->‘3‘
3、0与O要一样
#include <iostream>
using namespace std;
#include <cstdio>
#include <string>
#include <cstring>
#include <cctype>
string str0 = "_ABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
string str1 = "_A 3 HIL JM O 2TUVWXY51SE Z 8 0";
//»ØÎÄpalindrome
bool isPalindromeString(string str){
for(int i = 0, len = str.length(); i <= len/2; i++)
if(str[i] != str[len-i-1]) return 0;
return 1;
}
bool isMirroedString(string str){
for(int i = 0, len = str.length(); i <= len/2; i++){
if((str[i] == ‘0‘ && str[len-1-i]==‘O‘) || (str[i] == ‘O‘ && str[len-i-1]==‘0‘)) continue;
else if(str1[str0.find(str[i])] != str[len-i-1]) return 0;
}
return 1;
}
int main(){
//freopen("data.in", "r", stdin);
string string;
while(cin >> string){
if(isMirroedString(string)){
if(isPalindromeString(string)) cout << string << " -- is a mirrored palindrome.";
else cout << string << " -- is a mirrored string.";
}else{
if(isPalindromeString(string)) cout << string << " -- is a regular palindrome.";
else cout << string << " -- is not a palindrome.";
}
cout << "\n\n";
}
return 0;
}
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原文地址:http://www.cnblogs.com/wbstackpop/p/4298791.html