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select * from
(
select c.company_id,  c.company_name_1 C, a.address_line_1_soundex A ,
  rank() over (partition by c.company_id, a.address_line_1_soundex  order by a.company_address_id) r
from company c, company_address a
where c.company_id = a.company_id
) s where r = 1
order by c

select c.company_id,  c.company_name_1 C, a.address_line_1_soundex A ,
  rank() over (partition by c.company_id, a.address_line_1_soundex  order by a.company_address_id) r
from company c, company_address a
where c.company_id = a.company_id
order by c

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原文地址:http://www.cnblogs.com/yoyohappy/p/4354041.html